Given a binary array, find the maximum number of consecutive 1s in this array.

Example 1:

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Input: [1,1,0,1,1,1]
Output: 3
Explanation: The first two digits or the last three digits are consecutive 1s.
    The maximum number of consecutive 1s is 3.

Note:

  • The input array will only contain 0 and 1.
  • The length of input array is a positive integer and will not exceed 10,000

思路

维护并统计1出现的最大次数即可。

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class Solution(object):
    def findMaxConsecutiveOnes(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        res = []
        count = 0
        for i in nums:
            if (i == 1):
                count += 1
            else:
                res.append(count)
                count = 0
        res.append(count)
        return max(res)